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 Mathematics Qn
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By: Hoang Quang Anh (offline)  Friday, July 19 2013 @ 04:27 AM CDT (Read 863 times)  
Hoang Quang Anh

Could somebody help me with these questions?
1) There are some pupils in 6A and 6B classrooms. If 15 pupils from 6A were to move to 6B, 6B would have thrice as many pupils as 6A. If, instead, 15 pupils from 6B were to move to 6A, 6A would have twice as many pupils as 6B. How many pupils are there in the 6A classroom?

2) Xue Ying and Brian have some stickers between them. If Xue Ying gave 42 stickers to Brian, Brian would have four times as many stickers as Xue Ying. If, instead, Brian gave 42 stickers to Xue Ying, Xue Ying would have twice as many sticker as Brian. How many stickers does Xue Ying have?

3) Siti and Aloysius have some money between them. If , Siti gave $77 to Aloysius, Aloysius would have four times as much money as Siti. If, instead, Aloysius gave $77 to Siti, Siti would have thrice as much money as Aloysius. How much money does Siti have?

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By: echeewh (offline)  Friday, July 19 2013 @ 04:51 PM CDT  
echeewh

Hey Quang Anh,

In view that the 3 Questions are similar, I will only provide one worked solution to Q1. As for Q2 and Q3, I suggest that you first understand the worked solution for Q1 and then apply the same method / technique for your other two remaining questions. Thank you. (Q2 Ans: 78 ; Q3 Ans: $133)

Following is my worked solution for Q1:

Q1.

<If 15 moved from 6A to 6B>
6A : 6B
1 : 3

<Before>
6A: 1p + 15
6B: 3p - 15

<if 15 moved from 6B to 6A>
6A : 6B
2 : 1

6A: 1p + 15 + 15 = 1p + 30
6B: 3p - 15 - 15 = 3p - 30

So we have ...

1p + 30 = 2u -- (1)
3p - 30 = 1u -- (2)

Substitute (2) in (1):
1p + 30 = 2 × (3p - 30)
1p + 30 = 6p - 60
6p - 1p = 30 + 60
5p = 90
1p --> 90 ÷ 5 = 18

6A:
1p + 15 --> 18 + 15 = 33

=========

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

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By: Hoang Quang Anh (offline)  Saturday, July 20 2013 @ 01:06 AM CDT  
Hoang Quang Anh

Thanks, Edward.

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