
By: Strawberry (offline) Sunday, August 04 2013 @ 06:07 AM CDT (Read 794 times)



Strawberry 
Need help with this question
Ali and Ben had a total of 180 stickers at first. In the first game they played, Ali lost 3/5 of his stickers to Ben. IN the second game they played, Ben lost 2/7 of his stickers to Ali. As a result, the two boys have the same number of sticker now. How many stickers did Ben have at first?

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Registered: 01/31/09 Posts: 83





By: echeewh (offline) Sunday, August 04 2013 @ 06:34 PM CDT



echeewh 
Hey <strawberry>
Following is my worked solution:
As this is an internal transfer process, the total number of stickers both had were the same before and after.
Hence, number of stickers at the end = 180.
<after B lost (2/7) of his stickers to A>
A: 90
B: 90
Apply <work backwards> method, we have ...
(5/7)B = 90
(7/7)B = 90 × (7/5) = 126
B = 126
A = 90  36 = 54
<after A lost (3/5) to B>
(2/5)A = 54
(5/5)A = 54 × (5/2) = 135
A = 135
B = 126  81 = 45
Hence Ben had 45 stickers at first.
========
Trust this helps.
Do let me know again if this is different from your <Answerkey> or if there's further clarification.
Cheers,
Edward

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Registered: 04/21/11 Posts: 623



