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 By: Strawberry (offline)  Sunday, August 04 2013 @ 06:07 AM CDT (Read 859 times)
Strawberry

Need help with this question

Ali and Ben had a total of 180 stickers at first. In the first game they played, Ali lost 3/5 of his stickers to Ben. IN the second game they played, Ben lost 2/7 of his stickers to Ali. As a result, the two boys have the same number of sticker now. How many stickers did Ben have at first?

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Registered: 01/31/09
Posts: 83

 By: echeewh (offline)  Sunday, August 04 2013 @ 06:34 PM CDT
echeewh

Hey <strawberry>

Following is my worked solution:

As this is an internal transfer process, the total number of stickers both had were the same before and after.

Hence, number of stickers at the end = 180.

<after B lost (2/7) of his stickers to A>

A: 90
B: 90

Apply <work backwards> method, we have ...

(5/7)B = 90
(7/7)B = 90 × (7/5) = 126
B = 126
A = 90 - 36 = 54

<after A lost (3/5) to B>

(2/5)A = 54
(5/5)A = 54 × (5/2) = 135
A = 135
B = 126 - 81 = 45

Hence Ben had 45 stickers at first.

========

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

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