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 Forum Index >  Test Paper Related >  Primary 6 Matters
 Math (Answer is 16)
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By: vivilau1112 (offline)  Tuesday, August 06 2013 @ 06:15 AM CDT (Read 598 times)  
vivilau1112

Hello everyone! I can't seem to understand the answer for this. I would appreciate someone's help.

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By: echeewh (offline)  Tuesday, August 06 2013 @ 05:06 PM CDT  
echeewh

Hey <vivilau1112>,

//updated
7/8/13, 8 pm.
//


1st line of the <Answerkey> appears to have typo error. It should be:

J -> p + 40 = 3u - 40 { not 2u } .

The rest of it appears to be in order.

//Perhaps you need some further explanation

<after J gave K $40>
K : J
2 : 1

<before>
K: 2p - 40
J: 1p + 40

<after K gave J $40>

K : J
1 : 3

<before>
K: 1u + 40
J: 3u - 40

Equate the above 2 <before> models for K, J. And you have ...

J:
1p + 40 = 3u - 40
1p = 3u - 80
2p = 6u - 160 -- (1)

K:
2p - 40 = 1u + 40
2p = 1u + 80 -- (2)

Substitute (1) into (2):
6u - 160 = 1u + 80

And I think you can work out the rest on your own

========

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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