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 P5 Maths 2011 Ai Tong Paper 2 Qn 8
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By: psiewpeng (offline)  Monday, August 19 2013 @ 09:48 PM CDT (Read 1114 times)  
psiewpeng

Hi.

Can anyone please help me with this question? Not sure how to get the answer. Thanks

Three children sold some fun fair tickets. Alex sold 5/8 of the tickets. Bei Shan sold 36 tickets fewer than Alex. Chai Lian sold 20 tickets. How many tickets did they sell altogether? ( answer- 64 tickets)

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By: echeewh (offline)  Monday, August 19 2013 @ 11:26 PM CDT  
echeewh

Hello <psiewpeng>,

Following is my worked solution:

A: (5/8)total
B: (5/8)total - 36
C: 20

A + B + C = (8/8)total
(5/8)total + (5/8)total - 36 + 20 = (8/8)total
5u + 5u - 36 + 20 = 8u
10u - 8u = 36 - 20
2u --> 16
1u --> 8

Total = 8u --> 8 × 8 = 64

==========

Trust this helps.

Do let me know again if there's further clarifications.

Cheers,
Edward

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By: psiewpeng (offline)  Thursday, August 22 2013 @ 02:09 AM CDT  
psiewpeng

Thanks Edward. However if I need to represent it using model diagram, can you help? Thanks

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By: echeewh (offline)  Thursday, August 22 2013 @ 04:27 AM CDT  
echeewh

Hey

As requested, here is the <Model> alternative:

*** - for alignment purpose


|----|----|----|----|----|----|----|----|
<--------- A --------><--><-20-->
******************** B *** C

From model,
B + C sold the remaining 3u of tickets

Given C sold 20 and B sold 36 tickets less than A,
C = 20
B = 5u - 36

B + C = 3u
5u - 36 + 20 = 3u
5u - 3u = 36 - 20
2u --> 16
1u --> 8

Total tickets sold = 8u
8u --> 8 × 8 = 64

==========

Trust this helps.

Do let me know again if there's further clarifications.

Cheers,
Edward.

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Registered: 04/21/11
Posts: 627

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