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 By: T0116060A (offline)  Friday, September 06 2013 @ 10:39 PM CDT (Read 559 times)
T0116060A

At a 2-day Health Conference, each participant was charged \$25 per day. On the first day, the number of male participants was 70 more than the number of female participants. On the second day, the number of male participants decreased by 10% but the number of female participants increased by 5%. Given that there were 453 participants on the second day, how much money was collected at the conference on the first day?

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Registered: 08/10/13
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 By: jo sarah (offline)  Friday, September 06 2013 @ 11:05 PM CDT
jo sarah

At a 2-day Health Conference, each participant was charged \$25 per day. On the first day, the number of male participants was 70 more than the number of female participants. On the second day, the number of male participants decreased by 10% but the number of female participants increased by 5%. Given that there were 453 participants on the second day, how much money was collected at the conference on the first day?

Solution:

Let there be 10u of female on 1st day.

..................female (F).............male (M)
1st day:.........10u...................10u + 70
2nd day........10.5u..................9u + 63

Therefore, 10.5u + 9u + 63 ---> 453
So that,.......19.5u ----> 453 - 63 = 390
And,...............1u -----> 390 / 19.5 = 20

Thus, there are 20u + 70 = 20 x 20 + 70 = 470 participants on 1st day,
So collection then = \$25 x 470 = \$11750

Hope this helps, Cheerio.

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Registered: 03/20/12
Posts: 111

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