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 Forum Index >  Test Paper Related >  Primary 6 Matters P6 Maths! 2012 Prelims St Hilda's Paper 2 Q3 & Q5
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 By: geniuskids (offline)  Monday, September 09 2013 @ 02:40 AM CDT (Read 846 times)
geniuskids

Hi there, just need to clarify Q3- My answer (worked out twice) is 27 but answer key is 25.

Am I correct?

As for Q5, I managed to get the answer but I did it by listing down manually. It's rather tedious.
Is there a formula for such pattern question?

Thanks

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Registered: 11/12/11
Posts: 169

 By: jo sarah (offline)  Monday, September 09 2013 @ 04:34 AM CDT
jo sarah

Hi, for Q3, your solution up to 21 days is ok
Then, there would be 105 g of flour, right?

Well, you assumed she starts from a Monday, and that's why you subtracted 60 g, leaving you with 45 g, etc.

BUT, note question asks for the least no. of days. Well, could the 21 days then have ended on a Thursday, so that the 105 g would be used from Fri to Sun, using up 90 g, leaving 15 g for the Mon that follows?

Thus is the answer 21 + 4 = 25.

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Registered: 03/20/12
Posts: 111

 By: jo sarah (offline)  Monday, September 09 2013 @ 07:13 AM CDT
jo sarah

For Q5, (oops, hope table doesn't get messed up!)
In the table here, I'll put in the quotients when each original entry is divided by 5 (as you should have observed they are multiples of 5)
Column.........A.........B.........C.........D
Row 1.............0.........1.........2..........3
Row 2.............6.........5.........4..........3
Row 3.............6.........7.........8..........9
Row 4............12.......11.......10.........9
Row 5............12.......13.......14........15, etc.

Observe: each ODD row ends in column D having row no. x 3
and each EVEN row starts with column A having row no. x 3

And 430 / 5 = 86, which isn't a multiple of 3, I'll look to add 1 to it, giving 87 which divides by 3.
So 430 should be in a row ENDing in a no. divisible by 3.
And, since you have to add 1 to get a no. Divisible by 3, it must be in column C

Now, the row no. Is given by 87 / 3 = 29, I.e. row 29

Cheerio! Hope this explains.

To answer, is there a formula?
Yes and no....pattern questions are as the name implies: you have to learn to observe patterns to get the formula.

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Registered: 03/20/12
Posts: 111

 By: echeewh (offline)  Monday, September 09 2013 @ 08:24 PM CDT
echeewh

Hi <geniuskids>

My worked solution as part of the alternative:

Odd rows of Col D is a multiple of 15 of that row number.
I.e. 1D = 1 × 15 = 15; 2D = 3 × 15 = 45; and so on.

Even rows of Col A is also a multiple of 15 of the row number itself.
I.e. 2A = 2 × 15 = 30; 4A = 4 × 15 = 60; and so on.

Given a number of 430, it will be in Col C as a number ending with digit '0' in Col A must be a multiple of 3.

To determine which Row is 430 in , 430 is not a multiple of 15, but is a number between 420 and 435, which are multiples of 15 (as shown below).

420 ÷ 15 = 28 (Col A)
435 ÷ 15 = 29 (Col D)

As we know 430 must be in Col C, hence it will be in 29 C.

Remarks:
Finding the pattern or 'code' is essential to answering the entire question. Usually when you have pattern questions given Figure number, Pattern number or Row number, etc., strive to find a pattern related to the Figure number, Pattern number or Row number itself. That's about it all , and Good Luck !!

========

Trust this helps clarify.

Cheers,
Edward

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Registered: 04/21/11
Posts: 627

 By: geniuskids (offline)  Monday, September 09 2013 @ 11:09 PM CDT
geniuskids

Hi all, yes, I understand yr solutions now! thank you very much!

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Registered: 11/12/11
Posts: 169

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