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 By: geniuskids (offline)  Monday, September 09 2013 @ 03:41 AM CDT (Read 872 times)
geniuskids

Hi there, I am quite weak on such average question. Pls help me!

Thank You

Active Member

Registered: 11/12/11
Posts: 169

 By: jo sarah (offline)  Monday, September 09 2013 @ 04:16 AM CDT
jo sarah

Let the no. of tumblers bought be 1u. at first.
Then, he paid. \$11u at first.
When he bought another at \$37, the total sum of money = \$( 11u + 37 ),
Which is equal to ( 1u + 1 ) x \$ 13 = \$ (13u + 13 )

So, 13u + 13 = 11u + 37
Therefore, 2u = 24
giving, 1u = 12

That is, he bought 12 tumblers.

Cheerio!

Regular Member

Registered: 03/20/12
Posts: 111

 By: jo sarah (offline)  Monday, September 09 2013 @ 04:16 AM CDT
jo sarah

Let the no. of tumblers bought be 1u. at first.
Then, he paid. \$11u at first.
When he bought another at \$37, the total sum of money = \$( 11u + 37 ),
Which is equal to ( 1u + 1 ) x \$ 13 = \$ (13u + 13 )

So, 13u + 13 = 11u + 37
Therefore, 2u = 24
giving, 1u = 12

That is, he bought 12 tumblers.

Cheerio!

Regular Member

Registered: 03/20/12
Posts: 111

 By: 555 (offline)  Wednesday, September 11 2013 @ 04:19 AM CDT
555

Newbie

Registered: 08/25/13
Posts: 5

 By: geniuskids (offline)  Wednesday, September 11 2013 @ 09:59 AM CDT
geniuskids

Hi Jo_sarah, Thanks, managed to solve it!

Active Member

Registered: 11/12/11
Posts: 169

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