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Saturday, August 19 2017 @ 07:28 PM CDT
 Forum Index >  Test Paper Related >  Primary 6 Matters
 P6 Maths ! 2012 Prelims CBS Paper 2 Q5
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By: geniuskids (offline)  Monday, September 09 2013 @ 03:41 AM CDT (Read 825 times)  
geniuskids

Hi there, I am quite weak on such average question. Pls help me!

Thank You

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By: jo sarah (offline)  Monday, September 09 2013 @ 04:16 AM CDT  
jo sarah

Let the no. of tumblers bought be 1u. at first.
Then, he paid. $11u at first.
When he bought another at $37, the total sum of money = $( 11u + 37 ),
Which is equal to ( 1u + 1 ) x $ 13 = $ (13u + 13 )

So, 13u + 13 = 11u + 37
Therefore, 2u = 24
giving, 1u = 12

That is, he bought 12 tumblers.

Cheerio! Big Grin

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By: jo sarah (offline)  Monday, September 09 2013 @ 04:16 AM CDT  
jo sarah

Let the no. of tumblers bought be 1u. at first.
Then, he paid. $11u at first.
When he bought another at $37, the total sum of money = $( 11u + 37 ),
Which is equal to ( 1u + 1 ) x $ 13 = $ (13u + 13 )

So, 13u + 13 = 11u + 37
Therefore, 2u = 24
giving, 1u = 12

That is, he bought 12 tumblers.

Cheerio! Big Grin

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Registered: 03/20/12
Posts: 111

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By: 555 (offline)  Wednesday, September 11 2013 @ 04:19 AM CDT  
555

Laughing Out Loud Smile Cool Razz

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By: geniuskids (offline)  Wednesday, September 11 2013 @ 09:59 AM CDT  
geniuskids

Hi Jo_sarah, Thanks, managed to solve it!

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