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Friday, July 21 2017 @ 09:34 PM CDT
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 p6 math 2012 sa1 st hilda Q14
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By: tchtby (offline)  Tuesday, September 10 2013 @ 08:35 PM CDT (Read 760 times)  
tchtby

Can someone help me with this qn.

thks

Alice had some apples and bananas.
3/4 of the apples and 6/7 of the bananas are in good conditions.
9/11 of the good fruits are apples
If the number of apples Alice had was 522 more than the number of bananas,
how many fruits did Alice have in all?

ans 774

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By: echeewh (offline)  Tuesday, September 10 2013 @ 11:36 PM CDT  
echeewh

Hi <tchtby>,

Following is my worked solution:

Q14.

(3/4)A = (9/11)total (of good fruits = Apples)
A = (9/11) × (4/3) = (12/11)total = (36/33)total

(6/7)B = (2/11)total (of good fruits = Bananas)
B = (2/11) × (7/6) = (7/33)total

Given the number of apples (A) was 522 more than the number of bananas (B ),

A - B = 522
(36/33)total - (7/33)total = 522
(29/33)total = 522
(1/33)total = 18

Total fruits = A + B
= (36/33)total + (7/33)total
= (43/33)total
= 43 × 18 = 774

========

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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