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 By: tchtby (offline)  Tuesday, September 10 2013 @ 08:35 PM CDT (Read 790 times)
tchtby

Can someone help me with this qn.

thks

Alice had some apples and bananas.
3/4 of the apples and 6/7 of the bananas are in good conditions.
9/11 of the good fruits are apples
If the number of apples Alice had was 522 more than the number of bananas,
how many fruits did Alice have in all?

ans 774

Newbie

Registered: 10/15/12
Posts: 13

 By: echeewh (offline)  Tuesday, September 10 2013 @ 11:36 PM CDT
echeewh

Hi <tchtby>,

Following is my worked solution:

Q14.

(3/4)A = (9/11)total (of good fruits = Apples)
A = (9/11) × (4/3) = (12/11)total = (36/33)total

(6/7)B = (2/11)total (of good fruits = Bananas)
B = (2/11) × (7/6) = (7/33)total

Given the number of apples (A) was 522 more than the number of bananas (B ),

A - B = 522
(36/33)total - (7/33)total = 522
(29/33)total = 522
(1/33)total = 18

Total fruits = A + B
= (36/33)total + (7/33)total
= (43/33)total
= 43 × 18 = 774

========

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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