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 By: Strawberry (offline)  Thursday, September 12 2013 @ 12:52 PM CDT (Read 531 times)
Strawberry

A telematch had a number of male and female participants. For every 3 male participants, there were 5 female participants. Midway, another 12 female participants and 21 male participants joined the telematch. In the end, the ratio of male to female participants was 3:4. How many male participants were at the telematch in the end?

Regular Member

Registered: 01/31/09
Posts: 83

 By: echeewh (offline)  Thursday, September 12 2013 @ 06:01 PM CDT
echeewh

Hello <Strawberry>,

Following is my worked solution:

<before>
M : F
3 : 5

<process>
M: + 21
F: + 12

<after>
M : F
3 : 4

This is a typical "Changed Qtys" concept type model question and can use the <Cross Multiply> method to solve it.

(3u + 21) / 3 = (5u + 12) / 4
4 × (3u + 21) = 3 × (5u + 12)
12u + 84 = 15u + 36
15u - 12u = 84 - 36
3u --> 48
1u --> 16

Number of Male participants at the end:
= 3u + 21
--> (3 × 16) + 21
= 48 + 21 = 69

=========

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers & All the very best
Edward

Active Member

Registered: 04/21/11
Posts: 627

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