
By: iyap (offline) Friday, September 13 2013 @ 05:45 AM CDT (Read 1306 times)



iyap 
Hi I have the following question (see attachment) that I hope to get help to solve. I know how to solve algebra way but not the heuristic way  woud like to ensure that my girl learns the right way. Thanks.

Newbie
Registered: 12/31/06 Posts: 10





By: jo sarah (offline) Friday, September 13 2013 @ 08:08 AM CDT



jo sarah 
Hi, I am having problem accessing your "attachment", so can't figure which question you need help in. If possible, how about typing the question?
By and large, if your child have no problem handling algebra, there is nothing wrong solving using algebra. A solution that is correct is correct; many questions can be solved using more than one approach.
Let me know how i can help.

Regular Member
Registered: 03/20/12 Posts: 111





By: echeewh (offline) Friday, September 13 2013 @ 08:27 PM CDT



echeewh 
Hey <iyap>
Guess u forgot to put in your attachment of the question here . Can you pls put in the attachment of your question or at least indicate the paper and question number and for which year ??
Thank you ,
Edward

Active Member
Registered: 04/21/11 Posts: 627





By: iyap (offline) Saturday, September 14 2013 @ 02:25 AM CDT



iyap 
apologies...i am a confirmed newbie first time posting. just realised that the attachment file format is not compatible for upload. here's the test paper  question 16.

Newbie
Registered: 12/31/06 Posts: 10





By: echeewh (offline) Saturday, September 14 2013 @ 06:57 PM CDT



echeewh 
Hi <iyap>
Following is my worked solution:
<Pizzas Recd>
G : B
3 : 1
<Number of Children>
G : B
1 : 1
Given each boy took (2/9)pizza and each girl took (1/6)pizza,
Number of pizzas eaten:
B = 1u × (2/9) = (2/9)u
G = 1u × (1/6) = (1/6)u
Since the boys finished all the pizzas,
(2/9)u = 1p  (1)
And the girls received 3 times as many as boys,
3p = 3 × (2/9)u = (2/3)u
Pizzas left by girls:
= (2/3)u  (1/6)u = (3/6)u
Given that girls had 4 1/2 pizzas left,
(3/6)u = 4 1/2 = (9/2) pizzas
1u > (9/2) × (6/3) = 9
Substitute in (1)
1p = (2/9)u = (2/9) × 9 = 2 pizzas
Total number of pizzas:
4p = 4 × 2 = 8 pizzas
=========
Trust this helps.
Do let me know again if there's further clarifications.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 627





By: iyap (offline) Sunday, September 15 2013 @ 03:29 AM CDT



iyap 
This is really helpful. Thanks

Newbie
Registered: 12/31/06 Posts: 10





By: jo sarah (offline) Monday, September 16 2013 @ 12:57 AM CDT



jo sarah 
Hi, this is my simple solution:
This is a onevariable question.
Since there is an equal no. of girls and boys, we assign the no. of pizzas as follows:
To the girls: 3u
To the boys: 1u
Thus, total no. of pizzas will be 4u.
Now, we find the no. of girls and also no. of boys based on what they eat: each girl ate 1/6 and each boy 2/9 of a pizza.
The no. of girls = (3u  4.5) / (1/6) = no. of boys = 1u / (2/9)
Therefore,
(3u  4.5) x (6/1) = 1u x (9/2)
18u  27 = 4.5u
And, 1u = 2
Therefore, there are 4 x 2 = 8 pizzas.
Cheerio!

Regular Member
Registered: 03/20/12 Posts: 111



