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 Forum Index >  Test Paper Related >  Primary 6 Matters 2013 P6 Prelims ! Maths! ACS Paper 2 Q13(b) and 18 (b)
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 By: geniuskids (offline)  Friday, September 13 2013 @ 10:31 AM CDT (Read 2620 times)
geniuskids

Hi there, please find attached. Managed to solve Parts A for both questions but I need help on Parts B

Q13a) 5280 cm3
Q13b) 960 cm3 (this is the one I needed help on)

Q18a)7.74cm2
Q18b)9.12cm2 (this is the one I needed help on)

Active Member

Registered: 11/12/11
Posts: 169

 By: echeewh (offline)  Saturday, September 14 2013 @ 08:15 AM CDT
echeewh

Hey <geniuskids>,

//Updated 15/9/13, 1335
Q18 worked solution was posted as attachment .
//

Q18 will posted in due course.

Following is my worked solution for Q13:

Q13.

(a)
Vol in A (at first)
= 20 × 12 × 22 = 5280 cm3

(b)
Given that after some water was poured from A to B, the height of water in A became 3 times that of B,

new height of water in A = 3h, where h = height of water in B

Vol of water poured out from A:
= 20 × 12 × (22 - 3h) {note: decrease in height of water in A}
= 5280 - 720h -- (1)

Vol of water in B:
= 16 × 10 × h
= 160h -- (2)

Since (1)=(2),

5280 - 720h = 160h
160h + 720h = 5280
880h = 5280
h = 6 cm

Vol of water in B:
= 160h
= 160 × 6
= 960 cm3

==========

Trust this helps.

Do let me know again if there's further clarifications.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: echeewh (offline)  Sunday, September 15 2013 @ 12:33 AM CDT
echeewh

Hi <geniuskids>,

Pls refer to attached for worked solution to Q18.

All the best to your PSLE,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: geniuskids (offline)  Sunday, September 15 2013 @ 01:34 AM CDT
geniuskids

Hi Edward,

Now I managed to get the answers.

Thank you for your well wishes!

Cheers

Active Member

Registered: 11/12/11
Posts: 169

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