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 By: tchtby (offline)  Tuesday, September 17 2013 @ 07:35 AM CDT (Read 1035 times)
tchtby

pls help me sole this qn

frederic had a candy bag which contained 35 chocolate bars and 50 sweets.
ryan had another candy bag which contained 45 chocolate bars and 10 sweets.
After Frederic gave ryan some chocolate bars and sweets, 40% of frederic's candy bag contain chocolate bars and 30% of ryan's candy bag contained sweets.
How many chocolate bars and sweets did frederic give to ryan altogether?

ans 25

Newbie

Registered: 10/15/12
Posts: 13

 By: echeewh (offline)  Tuesday, September 17 2013 @ 04:13 PM CDT
echeewh

Hi <tchtby>,

Following is my worked solution:

*** - for alignment purpose

<Before>
Fc : Fs ***** Rc : Rs
35 : 50 ***** 45 : 10

<F gave some c, s to R>

<After>
Fc : Fs ***** Rc : Rs
40 : 60 ***** 70 : 30
2 : 3 ******** 7 : 3

As this is an internal transfer, the <Unchanged Total> concept can be applied. I.e. total number of c in both F,R candy bags <before> and <after> has to be the same. Likewise , the total number of s.

Let the <After> ratios in F candy bag be part (p) qty , while that in R candy bag be unit (u) qty.

<c>
2p + 7u = 35 + 45
2p + 7u = 80 --- (1)

<s>
3p + 3u = 50 + 10
3p + 3u = 60 --- (2)

Eliminate (u) qty:

(1)x3:
6p + 21u = 240 --- (3)

(2)x7:
21p + 21u = 420 --- (4)

(4)-(3):
21p - 6p = 420 - 240
15p --> 180
1p --> 12

Number of c , s in F candy bag <After>:
= 2p + 3p
= 5p --> 5 × 12 = 60

Number of c , s in F candy bag <before>:
= 35 + 50 = 85

Gave:
85 - 60 = 25

Hence, F gave 25 chocolate bars and sweets altogether to R.

==========

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: tchtby (offline)  Tuesday, September 17 2013 @ 08:51 PM CDT
tchtby

thank you very much

Newbie

Registered: 10/15/12
Posts: 13

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