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 Tao Nan 2009 P5 SA1 Q18
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By: parent603 (offline)  Monday, February 24 2014 @ 01:04 AM CST (Read 716 times)  
parent603

Would appreciate if u could provide explanation to solve this q. Thanks.

Leela and Kumar shared a sum of money.
Leela's share was $90 less than Kumar's.
After Kumar gave 1/7 of his share to Leela,Leela had $10 more than Kumar.
a) how much did Leela have at first? (Ans: $260)
b) what was the sum of money. (Ans: $610)

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By: echeewh (offline)  Monday, February 24 2014 @ 02:32 AM CST  
echeewh

Hey <parent603>

Following is my worked solution (with brief explanation):

<After>

After K gave 1/7 of his share to L, K left with 6 parts. Hence, the model becomes ...

K: |----|----|----|----|----|----|
L: |----|----|----|----|----|----|10|

<Before>
Apply <work backward> method, K would have that 1 part {K did not give 1/7 of his share to L} while L would not have that 1 part. Given that L's share was $90 less than K, the model becomes ...

K: |----|----|----|----|----|----|----|
L: |----|----|----|----|----|10|<90>

2u --> 100
1u --> 50

(a)
L (at first) = 5u + 10
5u + 100 --> (5 × 50) + 10
= 250 + 10
= $260

(b)
Sum of money (K + L) (at first) = 12u + 10
12u + 10 --> (12 × 50) + 10
= 600 + 10
= $610

=========

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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