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 Help on one Sec 1 Math question
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By: Kuro (offline)  Thursday, June 19 2014 @ 10:36 PM CDT (Read 919 times)  

Please refer to attachment, thanks. There is no answer key.

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By: jo sarah (offline)  Monday, June 23 2014 @ 08:55 AM CDT  
jo sarah

hi Kuro

the product of the HCF and LCM is the product of the two numbers.

So, just multiply the two given LCM and HCF together and any combinations of factors can be the two numbers, so long as you don't choose either to be the LCM or HCF given.

[don't worry about answer key, don't need to depend on it Smile]

Qn. If the H.C.F and the L.C.M of two numbers are 3x5^3x7^2 and 3^2x5^4x7^2x11
respectively, find all the possible values of the two numbers, given that none of them is
the H.C.F or the L.C.M.

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