
By: shino.dino (offline) Monday, July 07 2014 @ 11:22 AM CDT (Read 1397 times)



shino.dino 
Hi, need help in these two maths qns. thanks and appreciated
1) Bag X and Bag Y contained some marbles. Bag X had 304marbles fewer than Bag Y. After 52marbles from Bag X were taken out and put into Bag Y, there were five times as many marbles in Bag Y as in Bag X. How many marbles were there in Bag Y at first?
ans: 458
2) A certain number of beads can be arranged in exactly 18beads per row. If the beads are arranged in rows of 11, there will be 8 more rows and 3 beads left over. How many beads are there altogether?
ans: 234

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Registered: 03/12/10 Posts: 8





By: echeewh (offline) Tuesday, July 08 2014 @ 12:18 AM CDT



echeewh 
Hey <shino.dino>
Following are my worked solutions :
Q1.
You should use model and apply the <Before and After> concept as follows
*  for alignment purpose
<before>
X 
Y < 304 >
<after>
* <1u>
X <52>
Y < 304 ><52>
* < 5u >
Using <Gap & Difference> method, we have ...
5u  1u > 52 + 304 + 52
4u > 408
1u > 102
Y (at first) = 5u  52
5u  52 > (5 × 102)  52
= 510  52
= 458
======
Q2
If these beads are arranged in 18 beads per row, let the number of rows be 1u.
If these beads are arranged in 11 beads per row, there will be (1u + 8) rows and 3 beads left over.
Hence, we have ...
Total beads (18 beads/row) = Total beads (11 beads/row)
1u × 18 = [(1u + 8) × 11] + 3
18u = 11u + 88 + 3
18u  11u > 91
7u > 91
1u > 13
Hence, total number of beads = 18u
18u > 18 × 13 = 234
=========
Trust these help.
Do let me know if there're further clarifications.
Cheers,
Edward

Active Member
Registered: 04/21/11 Posts: 627





By: shino.dino (offline) Sunday, July 27 2014 @ 07:31 PM CDT



shino.dino 

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Registered: 03/12/10 Posts: 8



