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 By: shino.dino (offline)  Monday, July 07 2014 @ 11:22 AM CDT (Read 1397 times)
shino.dino

Hi, need help in these two maths qns. thanks and appreciated

1) Bag X and Bag Y contained some marbles. Bag X had 304marbles fewer than Bag Y. After 52marbles from Bag X were taken out and put into Bag Y, there were five times as many marbles in Bag Y as in Bag X. How many marbles were there in Bag Y at first?
ans: 458

2) A certain number of beads can be arranged in exactly 18beads per row. If the beads are arranged in rows of 11, there will be 8 more rows and 3 beads left over. How many beads are there altogether?
ans: 234

Newbie

Registered: 03/12/10
Posts: 8

 By: echeewh (offline)  Tuesday, July 08 2014 @ 12:18 AM CDT
echeewh

Hey <shino.dino>

Following are my worked solutions :

Q1.

You should use model and apply the <Before and After> concept as follows

* - for alignment purpose

<before>

X |-----------|
Y |-----------<-- 304 -->|

<after>

* <1u>
X |----|<52>
Y |-----------<-- 304 --><52>|
* <------------- 5u ------------->

Using <Gap & Difference> method, we have ...

5u - 1u --> 52 + 304 + 52
4u --> 408
1u --> 102

Y (at first) = 5u - 52
5u - 52 --> (5 × 102) - 52
= 510 - 52
= 458

======

Q2

If these beads are arranged in 18 beads per row, let the number of rows be 1u.

If these beads are arranged in 11 beads per row, there will be (1u + 8) rows and 3 beads left over.

Hence, we have ...

1u × 18 = [(1u + 8) × 11] + 3
18u = 11u + 88 + 3
18u - 11u --> 91
7u --> 91
1u --> 13

Hence, total number of beads = 18u
18u --> 18 × 13 = 234

=========

Trust these help.

Do let me know if there're further clarifications.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: shino.dino (offline)  Sunday, July 27 2014 @ 07:31 PM CDT
shino.dino

Thanks

Newbie

Registered: 03/12/10
Posts: 8

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