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Saturday, June 24 2017 @ 12:12 PM CDT
 Forum Index >  Test Paper Related >  Primary 6 Matters
 Maris Stellla 2013 SA2 Questions
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By: parent603 (offline)  Sunday, July 13 2014 @ 05:11 AM CDT (Read 2280 times)  
parent603

Hi,

Appreciate if you could help to provide solutions to Q25 and Q26.

Thanks for your help!

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By: echeewh (offline)  Sunday, July 13 2014 @ 01:32 PM CDT  
echeewh

Hey < parent603 >,

Following is my worked solution for Q26.


angle EFC = 180 - 50 = 130 { sum of internal angles between // lines }

given CBEF is a rhombus, BF is a diagonal that bisects angle EFC.

Hence, angle BFE = angle BFC = 130 ÷ 2 = 65

angle BCF = angle BEF = 50 { diagonally opposite angles are equal }

Given ABCD is a square, angle BCD = 90.

Hence, angle DCF = 90 + 50 = 140

Given triangle DCF is isosceles { CD = CF },
angle CFD = angle CDF = (180 - 140) ÷ 2 = 20

Hence, angle BFG = 65 - 20 = 45°

========

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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By: echeewh (offline)  Monday, July 14 2014 @ 02:16 AM CDT  
echeewh

Hey < parent603 >,

Kindly refer to attachment for my worked solution to q25.

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

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