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Friday, July 21 2017 @ 09:33 PM CDT
 Forum Index >  Test Paper Related >  Primary 6 Matters
 Primary 6 Math
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By: Chanon (offline)  Tuesday, August 26 2014 @ 08:55 AM CDT (Read 1440 times)  
Chanon

Hi all,
Could anyone can tell me the solution for the following question:

Kor Ming had an equal number of roses, tulips and daisies. He gave away 37 roses, some tulips and daisies. He had twice as many tulips as daisies left. He had 19 fewer roses than tulips left. The total number of flowers left was 116. How many daisies were given away?

Yours sincerely,
Chanon

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By: w13158 (offline)  Tuesday, August 26 2014 @ 08:20 PM CDT  
w13158

Kor Ming had an equal number of roses, tulips and daisies. He gave away 37 roses, some tulips and daisies. He had twice as many tulips as daisies left. He had 19 fewer roses than tulips left. The total number of flowers left was 116. How many daisies were given away?

At first,
Rose=Tulip=Daisies

At the end, total no of flowers=116
D=1U
T=2U
R-2U-19

To calcualte each U,
116+19 divide by 5
=135/5 = 27

Since Rose is given absolute number, calculate how many roses at first,
R=(2U-19)+37
=(2x27-19)+37
=72

So, at first Tulip=Daisies=Rose=72
Daisies=72-1U
=72-27
=45

Ans: 45 Daisies
Cheers

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