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 By: apache (offline)  Thursday, September 18 2014 @ 10:09 AM CDT (Read 1461 times)
apache

Dear All,

Appreciate your help to enlighten the correct method and answer of solving below maths question:

Question
What is the value of 2000 - 1999 + 1998 - 1997 + ... + 4 - 3 + 2 - 1 ?

(1) 1
(2) 1000
(3) 1999
(4) 4

Eric

Newbie

Registered: 09/08/14
Posts: 2

 By: echeewh (offline)  Thursday, September 18 2014 @ 12:49 PM CDT
echeewh

Hey <apache>

Following is the worked solution:

Analyse the series of numbers in the pattern.
Every group/set of 2 numbers ( starting from left ) adds up to 1.
2000 - 1999 = 1
1998 - 1997 = 1
...
4 - 3 = 1
2 - 1 = 1

From 1 - 2000 (inclusive) there are 1000 groups/sets of these 2 numbers (adding to 1)

2000 ÷ 2 = 1000

hence, the sum of these 1000 groups/sets (of 1 each) is 1000

=======

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

 By: apache (offline)  Thursday, September 18 2014 @ 08:48 PM CDT
apache

Hi Edward,

Thank you so much for your help in solving this question.

It really helps.

Thank you once again.

Cheers!
Eric

Quote by: echeewh

Hey <apache>

Following is the worked solution:

Analyse the series of numbers in the pattern.
Every group/set of 2 numbers ( starting from left ) adds up to 1.
2000 - 1999 = 1
1998 - 1997 = 1
...
4 - 3 = 1
2 - 1 = 1

From 1 - 2000 (inclusive) there are 1000 groups/sets of these 2 numbers (adding to 1)

2000 ÷ 2 = 1000

hence, the sum of these 1000 groups/sets (of 1 each) is 1000

=======

Trust this helps.

Do let me know again if this is different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

Newbie

Registered: 09/08/14
Posts: 2

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