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 By: sundarshoba (offline)  Friday, April 17 2015 @ 11:45 PM CDT (Read 862 times)
sundarshoba

Some people attended a 2 day seminar. There were 120 more men than women on the first day of the seminar. The next day 1/12 of the men did not attend the seminar. However the number of womenwho attended on the second day was 7/ 6 of the number of women who were present on the first day. The overall attendance increased by 50. How many adults were present on the first day of the seminar?

Chatty

Registered: 12/31/06
Posts: 53

 By: echeewh (offline)  Saturday, April 18 2015 @ 05:40 AM CDT
echeewh

Hey <sundarshoba>

Following is my worked solution:

<Day 1>
M: 1u + 120
W: 1u

<Day 2>
M: (11/12) x (1u + 120) = (11u/12) + 110
W: (7/6) x 1u = (7u/6)

Given that overall attendance increased by 50, we have ...

<Day 2> - <Day 1> = 50
(11u/12) + 110 + (7u/6) - 2u - 120 = 50
(25u/12) - 2u --> 50 + 120 - 110
(25u - 24u)/12 --> 60
1u --> 12 x 60 = 720

Adults present on Day 1 = 2u + 120
2u + 120 --> (2 x 720) + 120 = 1560

======

Trust this helps.

Do let me know again if this is different from your <Anskey> or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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