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By: sundarshoba (offline)  Friday, April 17 2015 @ 11:45 PM CDT (Read 846 times)  
sundarshoba

Please assist to solve,

Some people attended a 2 day seminar. There were 120 more men than women on the first day of the seminar. The next day 1/12 of the men did not attend the seminar. However the number of womenwho attended on the second day was 7/ 6 of the number of women who were present on the first day. The overall attendance increased by 50. How many adults were present on the first day of the seminar?

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By: echeewh (offline)  Saturday, April 18 2015 @ 05:40 AM CDT  
echeewh

Hey <sundarshoba>

Following is my worked solution:

<Day 1>
M: 1u + 120
W: 1u

<Day 2>
M: (11/12) x (1u + 120) = (11u/12) + 110
W: (7/6) x 1u = (7u/6)

Given that overall attendance increased by 50, we have ...

<Day 2> - <Day 1> = 50
(11u/12) + 110 + (7u/6) - 2u - 120 = 50
(25u/12) - 2u --> 50 + 120 - 110
(25u - 24u)/12 --> 60
1u --> 12 x 60 = 720

Adults present on Day 1 = 2u + 120
2u + 120 --> (2 x 720) + 120 = 1560

======

Trust this helps.

Do let me know again if this is different from your <Anskey> or if there's further clarification.

Cheers,
Edward

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