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 By: khaye (offline)  Wednesday, May 06 2015 @ 03:09 AM CDT (Read 1850 times)
khaye

Please help me to answer thanks

1.Carmen and Ericia had a total of \$230. 2/5 of Carmen's money was \$40 more than 1/4 of Ericia's money.How much money had Ericia?
2.Bob and Carl saved a total of \$1416. 2/3 of Bob's savings was \$60 more than 1/5 of Carl's savings.How much money did Bob save?

Newbie

Registered: 02/19/15
Posts: 8

 By: echeewh (offline)  Wednesday, May 06 2015 @ 11:47 AM CDT
echeewh

Hey <khaye>,

Following are my worked solutions:

Both questions are very similar and use <Simultaneous> method to solve.

Q1.

C + E = 230 --- (1)

(2/5)C = (1/4)E + 40
(2/5)C - (1/4)E = 40 --- (2)

Common multiple of (5, 4) is 20:

(2)x20:
8C - 5E = 800 --- (3)

Eliminating C:

(1)x8:
8C + 8E = 1840 --- (4)

Comparing (3), (4):

(4)-(3):
8E - (- 5E) = 1840 - 800
8E + 5E = 1040
13E = 1040
E = 80

Ericia had \$80

======

Q2.

B + C = 1416 --- (1)

(2/3)B = (1/5)C + 60
(2/3)B - (1/5)C = 60 --- (2)

Common multiple of (3, 5) is 15:

(2)X15:
10B - 3C = 900 --- (3)

Eliminating C:

(1)x3:
3B + 3C = 4248 --- (4)

Comparing (3), (4):

(3)+(4):
10B + 3B = 900 + 4248
13B = 5148
B = 396

Bob saved \$396

=======

Trust the above help.

Do let me know again if these are different from your <Answerkey> or if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 623

 By: khaye (offline)  Friday, May 08 2015 @ 12:41 AM CDT
khaye

Thanks a lot Edward for the Big help..

Newbie

Registered: 02/19/15
Posts: 8

 By: echeewh (offline)  Sunday, June 07 2015 @ 01:08 AM CDT
echeewh

Hey <khaye> et al,

Apart from using <Simultaneous> method to solve these two problems, the <model> method can also be used as shown:

Q1.

*** - for alignment purpose

C |-----|<40> --> (2/5)C
E |-----| ***** --> (1/4)E

Apply <work backwards>

Split the equal portion of C, E into 2 units (u).

C |--|--|<40> --> (2/5)C
E |--|--| ***** --> (1/4)E

<Before>

(2/5)C = 2u + 40
(1/5)C = 1u + 20
(5/5)C = 5u + 100

(1/4)E = 2u
(4/4)E = 8u

Given Carmen (C) and Ericia (E) had a total of \$230, we have ...

13u + 100 --> 230
13u --> 230 - 100 = 130
1u --> 10

E (before) = 8u --> 8 × 10 = \$80

======

Trust this helps.

Do let me know again if there's further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 623

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