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 By: drstevewu (offline)  Tuesday, September 19 2017 @ 11:51 PM CDT (Read 3823 times)
drstevewu

Question: Three boys Alan, Ben And Carl had the same number of coins. Alan and Ben each had a mix of twenty-cents and fifty-cents coins. Alan had 7 twenty-cents coins while Ben had 17 twenty-cent coins. Carl had only fifty-cent coins. Ben used all his fifty-cent coins to buy stationery. He then had \$9.10 less than Carl. How many fifty-cents coins did Carl have? (the answer is 25 fifty-cents coins. I thought it was 24)

Thank you very much.

Junior

Registered: 04/20/10
Posts: 31

 By: echeewh (offline)  Thursday, September 21 2017 @ 04:55 PM CDT
echeewh

Hey <drstevewu> ,

Following pls find my worked solution.

Given that Ben (B ) used all his fifty-cent coins to buy stationery, B would have left with only 17 twenty-cent coins.

17 × 20 = 340

And this is \$9.10 less than Carl (C), we have ...

C = 910 + 340 = 1250

As C had only fifty-cent coins, we have ...

Qty of fifty-cent coins = 1250 ÷ 50 = 25

=====

Trust this helps.

Do let me know again if there is further clarification.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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