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Thursday, November 23 2017 @ 03:04 AM CST
 Forum Index >  Test Paper Related >  Primary 3 Matters
 P4 Maths
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By: fanny6573 (offline)  Wednesday, August 04 2010 @ 08:37 AM CDT (Read 1678 times)  
fanny6573

Hi can anyone help to solve this question?

Hanna paid $85.10 for a total of 10 brownies and pies. She had 2 more brownies than pies. Each pie cost $8.90 more than each brownie. How much did she pay for one pie?

Can we draw a model to solve the problem?

Thanks.

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By: lemofish (offline)  Wednesday, August 04 2010 @ 09:47 PM CDT  
lemofish

Hanna paid $85.10 for a total of 10 brownies and pies. She had 2 more brownies than pies. Each pie cost $8.90 more than each brownie. How much did she pay for one pie?

No. of pies=(10-2)/2=4
Each pie costs $8.90 more than each brownie.
Therefore, 4 pies cost 4x$8.90 =$35.60 more
Cost of each brownie= ($85.10-$35.60)/10=$4.95
Cost of each pie=$4.95+$8.90=$13.85

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By: rathanackumr (offline)  Monday, September 06 2010 @ 02:32 AM CDT  
rathanackumr

Model method attached. cheers

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By: tanhuimin (offline)  Monday, September 06 2010 @ 07:31 AM CDT  
tanhuimin

Method is no diff. from rathanackumr, but I would like to present the model is a slightly different view, which should be much easier for the student to understand the solution.

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By: fanny6573 (offline)  Monday, September 06 2010 @ 08:35 PM CDT  
fanny6573

Dear Huimin

Yes your method is more simply and easy to understand. Thank you.

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