
By: fanny6573 (offline) Wednesday, August 04 2010 @ 08:37 AM CDT (Read 1678 times)



fanny6573 
Hi can anyone help to solve this question?
Hanna paid $85.10 for a total of 10 brownies and pies. She had 2 more brownies than pies. Each pie cost $8.90 more than each brownie. How much did she pay for one pie?
Can we draw a model to solve the problem?
Thanks.

Junior
Registered: 07/19/10 Posts: 28





By: lemofish (offline) Wednesday, August 04 2010 @ 09:47 PM CDT



lemofish 
Hanna paid $85.10 for a total of 10 brownies and pies. She had 2 more brownies than pies. Each pie cost $8.90 more than each brownie. How much did she pay for one pie?
No. of pies=(102)/2=4
Each pie costs $8.90 more than each brownie.
Therefore, 4 pies cost 4x$8.90 =$35.60 more
Cost of each brownie= ($85.10$35.60)/10=$4.95
Cost of each pie=$4.95+$8.90=$13.85

Newbie
Registered: 07/29/10 Posts: 9





By: rathanackumr (offline) Monday, September 06 2010 @ 02:32 AM CDT



rathanackumr 
Model method attached. cheers

Junior
Registered: 07/22/10 Posts: 18





By: tanhuimin (offline) Monday, September 06 2010 @ 07:31 AM CDT



tanhuimin 
Method is no diff. from rathanackumr, but I would like to present the model is a slightly different view, which should be much easier for the student to understand the solution.

Junior
Registered: 12/31/06 Posts: 18





By: fanny6573 (offline) Monday, September 06 2010 @ 08:35 PM CDT



fanny6573 
Dear Huimin
Yes your method is more simply and easy to understand. Thank you.

Junior
Registered: 07/19/10 Posts: 28



