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 By: fanny6573 (offline)  Wednesday, August 04 2010 @ 08:37 AM CDT (Read 1727 times)
fanny6573

Hi can anyone help to solve this question?

Hanna paid \$85.10 for a total of 10 brownies and pies. She had 2 more brownies than pies. Each pie cost \$8.90 more than each brownie. How much did she pay for one pie?

Can we draw a model to solve the problem?

Thanks.

Junior

Registered: 07/19/10
Posts: 28

 By: lemofish (offline)  Wednesday, August 04 2010 @ 09:47 PM CDT
lemofish

Hanna paid \$85.10 for a total of 10 brownies and pies. She had 2 more brownies than pies. Each pie cost \$8.90 more than each brownie. How much did she pay for one pie?

No. of pies=(10-2)/2=4
Each pie costs \$8.90 more than each brownie.
Therefore, 4 pies cost 4x\$8.90 =\$35.60 more
Cost of each brownie= (\$85.10-\$35.60)/10=\$4.95
Cost of each pie=\$4.95+\$8.90=\$13.85

Newbie

Registered: 07/29/10
Posts: 9

 By: rathanackumr (offline)  Monday, September 06 2010 @ 02:32 AM CDT
rathanackumr

Model method attached. cheers

Junior

Registered: 07/22/10
Posts: 18

 By: tanhuimin (offline)  Monday, September 06 2010 @ 07:31 AM CDT
tanhuimin

Method is no diff. from rathanackumr, but I would like to present the model is a slightly different view, which should be much easier for the student to understand the solution.

Junior

Registered: 12/31/06
Posts: 18

 By: fanny6573 (offline)  Monday, September 06 2010 @ 08:35 PM CDT
fanny6573

Dear Huimin

Yes your method is more simply and easy to understand. Thank you.

Junior

Registered: 07/19/10
Posts: 28

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