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 By: sonialam04 (offline)  Thursday, August 19 2010 @ 07:49 PM CDT (Read 1524 times)
sonialam04

Kailing and Jim had a total of \$63. Kailing gave 0.3 of her share to Jim. Jim then gave 1/3 of the total amount of the money to his brother . In the end, all the 3 children had the same amount of money. How much money did Kailing have at first?

Newbie

Registered: 12/31/06
Posts: 1

 By: lemofish (offline)  Saturday, August 21 2010 @ 04:51 AM CDT
lemofish

Kailing and Jim had a total of \$63. Kailing gave 0.3 of her share to Jim. Jim then gave 1/3 of the total amount of the money to his brother . In the end, all the 3 children had the same amount of money. How much money did Kailing have at first?

Before:
Kailing=1U
Jim=1P

After:
Kailing=0.7U
Jim=2/3(1P+0.3U)=2/3P+0.2U

1U+1P=63
P=63-U...(1)
0.7U=2/3P+0.2U...(2)
0.7U=2/3(63-U)+0.6U
2.1U=126-2U+0.6U
3.5U=126
U=36

Therefore, kailing has \$36 at first.

Newbie

Registered: 07/29/10
Posts: 9

 By: nisalam (offline)  Wednesday, August 25 2010 @ 07:49 AM CDT
nisalam

I'm wondering if that is right. K, J and bro all have \$21 in the end. K had given away 0.3 of her money. That makes 0.7 of her money = \$21. So she had \$30 in the beginning, I think.

Junior

Registered: 04/29/10
Posts: 30

 By: nisalam (offline)  Wednesday, August 25 2010 @ 04:06 PM CDT
nisalam

Oops, I was wrong .... only the two had \$63. Missed that part. Sorry!

Junior

Registered: 04/29/10
Posts: 30

 By: jas.soliano (offline)  Thursday, August 26 2010 @ 12:55 PM CDT
jas.soliano

You can draw model to solve this. Primary Maths don't use algebra with two unknowns.

After model

K: I. I. I. I. I. I. I. I.
J: I. I. I. I. I

Jim gave away 1/3 of his money (includes 1/3 of the 3u given by K).
Therefore he had 2u from K + 2/3 of his own left.

From the model we know that 5u of K = 2u of J
Common multiple is 10, hence we cut 2u of J into 10 and 5u of K into 10.

K and J has 28u altogether now.
J gave away 1u of K and 1u of his own. That makes 2 + 5 = 7u
28 + 7 = 35

35u -> 63
1u -> 1.8

K has 20u at first before giving away 0.3, hence 20u -> 1.8 x 20 = 36

Newbie

Registered: 08/16/09
Posts: 6

 By: jas.soliano (offline)  Thursday, August 26 2010 @ 12:57 PM CDT
jas.soliano

Sorry my line model did not display well

Should be

K I.....I.....I.....I.....I.....I.....I.....I
J I.....I.....I..............I..............I

Newbie

Registered: 08/16/09
Posts: 6

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