
By: Dahlia98 (offline) Monday, September 27 2010 @ 07:47 PM CDT (Read 2687 times)



Dahlia98 
Need help on these questions.
During a sale, stall A and stall B were selling durians, each at $5 and $3 respectively. Before the sale, the price of the durians was the same at both stalls. A sum of $96 could be saved by buying 8 durians from each stall during the sale. How much could I save if I were to buy 4 durians from stall B?

Cinema admission tickets for children were priced at $8 each. There were 20 more boys than girls in the cinema from the first movie. For the second movie, the number of boys decreased by 10% but the number of girls increased by 5%. If there were 408 children at the second movie, how much money was collected from the sales of admission tickets for the first movie?

Thank you for helping!

Newbie
Registered: 11/03/09 Posts: 2





By: Laks (offline) Tuesday, September 28 2010 @ 12:54 AM CDT



Laks 
1. Cinema admission tickets for children were priced at $8 each. There were 20 more boys than girls in the cinema from the first movie. For the second movie, the number of boys decreased by 10% but the number of girls increased by 5%. If there were 408 children at the second movie, how much money was collected from the sales of admission tickets for the first movie?
Girls : Boys
1st movie : 100% : 100% + 20
2nd movie : 105% : 90 % + 18 ( decrease of 10%) 90 /100 x 20 = 18
105% + 90% + 18 = 408
195% = 408  18
1% = 2
(2 x 200) + 20 = 420
420 x $ 8 = $3360

Newbie
Registered: 12/31/06 Posts: 1





By: blessed (offline) Saturday, October 30 2010 @ 12:43 AM CDT



blessed 
save $28 for 4 durians for first question? Anyone with same answer?

Newbie
Registered: 12/31/06 Posts: 1





By: mary16 (offline) Wednesday, November 03 2010 @ 12:24 AM CDT



mary16 
During a sale, stall A and stall B were selling durians, each at $5 and $3 respectively. Before the sale, the price of the durians was the same at both stalls. A sum of $96 could be saved by buying 8 durians from each stall during the sale. How much could I save if I were to buy 4 durians from stall B?
Usual price of each durian
Stall A = $X + $5
Stall B = $Y + $3
$X + $5 = $Y + $3
$X = $Y  $2  (1)
8 * (X+Y) = $96
X + Y = $12  (2)
Substitute (1) into (2)
($Y  $2) + $Y = $12
2$Y = $14
$Y = $7  (3)
4 X $7 = $28
I would save $28 if I were to buy 4 durians from stall B.

Newbie
Registered: 10/24/10 Posts: 1





By: kennytan87 (offline) Wednesday, November 03 2010 @ 02:19 AM CDT



kennytan87 
Mary 16. I don't think Primary allows to solve alegbra and solve using simultaneous equation:
Suggested Solution:
Cost of durians during Sale:
A $5
B $3
Total cost from buying 8 from each stall (during sale):
$5 x 8 + $3 x 8 = $40 + $24
= $64
Total cost from buying 8 from each stall (without sale):
$64 + $96 = $160
Since 16 durians are bought & all are same price:
$160 / 16 = $10
Buying 4 how much can he save:
$10x4  $3x4 = $40  $12
= $28
He can save $28.
Hope it helps you in understanding.

Newbie
Registered: 05/31/10 Posts: 1



