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 By: Aliah (offline)  Wednesday, October 13 2010 @ 05:43 AM CDT (Read 1785 times)
Aliah

1) Andy and Benny have 80 books altogether. Benny and Colin have 70 books altogether.
Andy and Colin have 90 books altogether. How many books does each of them have?

2) A box contains 36 similar mirrors. The total mass of the box together with 3/4 of the mirrors
is 11.25kg lighter than that of the box with all the mirrors. The mass of each mirror is 5/7 of
mass of the box. What is the total mass of the box with the 36 mirrors?

3) A bookshop owner bought an equal number of files and exercise books. She spent 3/5 of her
money on the files and 1/4 of the remainder on exercise books. She could buy another 1200
exercise books with the rest of her money.

a) How many exercise books did she buy at first?

b) If each file cost \$2.50 more than each exercise book, what was the cost of an exercise book?

Thank You.

Newbie

Registered: 10/13/10
Posts: 3

 By: suz855 (offline)  Thursday, October 14 2010 @ 05:53 AM CDT
suz855

Q1. Given A+B=80
B+C=70
A+C=90

If we sum them altogether, we'll have 2 x (A+B+C) = 240, therefore, A+B+C = 120
Problem will then be solved, since A+B=80, therefore C = 40 & so on.....

Q2. Given the total mirrors were 36, therefore 1/4 of them will be 9 mirrors.

Since the mass of the box is constant, the 11.25kg will be the mass of the 9 mirrors, we can then find the mass of 1 mirror

(1mirror) --> 11.25 divide by 9 = 1.25kg
Given mass of 1 mirror is 5/7 the mass of the box, mass of box shall be 1.25 divided by 5 multiply by 7 which is 1.75kg.
Puting everything together 1.75kg + 36 x 1.25kg = 46.75kg

Q3. [ | ][ | ][ | ][ | ][ | ]
<-----------> <---->
files left

(left)--> 3u = 1200 books, therefore number of files equal to number of books which will be 400
Since given each file cost 2.50 more than a book, 400 files shall cost 400 x 2.50 = \$1000 more

5u --> 1000, therefore, 1u = 200

cost of a book = 200 divide 400 = \$0.5

Junior

Registered: 12/31/06
Posts: 16

 By: Aliah (offline)  Friday, October 15 2010 @ 07:49 AM CDT
Aliah

Quote by: suz855

Q1. Given A+B=80
B+C=70
A+C=90

If we sum them altogether, we'll have 2 x (A+B+C) = 240, therefore, A+B+C = 120
Problem will then be solved, since A+B=80, therefore C = 40 & so on.....

Q2. Given the total mirrors were 36, therefore 1/4 of them will be 9 mirrors.

Since the mass of the box is constant, the 11.25kg will be the mass of the 9 mirrors, we can then find the mass of 1 mirror

(1mirror) --> 11.25 divide by 9 = 1.25kg
Given mass of 1 mirror is 5/7 the mass of the box, mass of box shall be 1.25 divided by 5 multiply by 7 which is 1.75kg.
Puting everything together 1.75kg + 36 x 1.25kg = 46.75kg

Q3. [ | ][ | ][ | ][ | ][ | ]
<-----------> <---->
files left

(left)--> 3u = 1200 books, therefore number of files equal to number of books which will be 400
Since given each file cost 2.50 more than a book, 400 files shall cost 400 x 2.50 = \$1000 more

5u --> 1000, therefore, 1u = 200

cost of a book = 200 divide 400 = \$0.5

Thanks Suz855 for the solutions.

Newbie

Registered: 10/13/10
Posts: 3

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