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Friday, August 18 2017 @ 03:52 AM CDT
 Forum Index >  Test Paper Related >  Primary 6 Matters
 please help to solve pri.6 maths
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By: Andy (offline)  Sunday, June 12 2011 @ 03:32 AM CDT (Read 1517 times)  
Andy

A and B had a total of 1200 stickers . A gave 1/6 of his stickers to B .
B then gave 1/4 of the total number of stickers he had to A .
In the end , each of them had the same number of stickers .
How many stickers had A at first ?

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By: athamms (offline)  Sunday, June 12 2011 @ 05:48 AM CDT  
athamms

Quote by: Andy

A and B had a total of 1200 stickers . A gave 1/6 of his stickers to B .
B then gave 1/4 of the total number of stickers he had to A .
In the end , each of them had the same number of stickers .
How many stickers had A at first ?



For this type of question you must work "backwards"

==> B gave 1/4 of the total stickers he had to A, so he is left with 3 units (3 out of 4 units)
Now A has x units (his left over) + 1 unit from B. But A and B had equal number of stickers now.
This means x units = 2 units. So total number of units = 6 = 1200 stickers
Therefore 1 unit = 200 stickers.

Now A had x units = 400 stickers. And this is = 5/6 because he gave away 1/6 to B initally.
So A had 400/5 * 6= 480 stickers initially.

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By: Andy (offline)  Tuesday, June 14 2011 @ 03:31 AM CDT  
Andy

thanks athamms!!!!

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