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 By: shirley wee (offline)  Friday, June 15 2012 @ 11:55 AM CDT (Read 733 times)
shirley wee

Hi everyone! I am stuck with this question. Could you help me to solve me, please?

There was a total of 225 counters in Bags A, B, C, and D. 15 counters from Bag A were given away, 24 counters were added to Bag B, half of the counters in Bag C were sold and the number of counters in Bag D were doubled. As a result, there was an equal number of counters in each bag.
a) Find the number of counters in Bag B at first.
b) How many more counters were there in Bag C than Bag D at first.

Chatty

Registered: 02/28/12
Posts: 68

 By: echeewh (offline)  Saturday, June 16 2012 @ 08:02 PM CDT
echeewh

Hey Shirley

Following pls find the worked solution:

Use <Working Backward> method:

At end, theres 1u of A, B, C and D respectively.

<After>
A |-------------|
B |-------------|
C |-------------|
D |-------------|

Counters in Bag D not doubled;
Half of the counters in Bag C not sold;
24 counters not added to Bag B;
15 counters from Bag A were not given away;

<Before>
A |------|------|<-15->| -
B |----|<-24-> |-> 225
C |------|------|-----|-----| |
D |------| -

9u - 24 --> 225 - 15 = 210
9u --> 210 + 24 = 234
1u --> 26

(a) Number of Counters in B (at first) = 2u - 24
--> (2 x 26) - 24 = 28

(b) C - D (at first) = 4u - 1u = 3u --> 3 x 26 = 78

============================

Trust this helps.

Do let me know if this does not agree with your answerkey.

Cheers,
Edward

Active Member

Registered: 04/21/11
Posts: 627

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